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2x*x-3=1.25x^2
We move all terms to the left:
2x*x-3-(1.25x^2)=0
Wy multiply elements
2x^2-(1.25x^2)-3=0
We get rid of parentheses
2x^2-1.25x^2-3=0
We add all the numbers together, and all the variables
0.75x^2-3=0
a = 0.75; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·0.75·(-3)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3}{2*0.75}=\frac{-3}{1.5} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3}{2*0.75}=\frac{3}{1.5} =2 $
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